10x^2+57x-80=0

Solution for 10x^2+57x-80=0 equation:

10x^2+57x-80=0

a = 10; b = 57; c = -80;
Δ = b2-4ac
Δ = 572-4·10·(-80)
Δ = 6449
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(57)-\sqrt{6449}}{2*10}=\frac{-57-\sqrt{6449}}{20}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(57)+\sqrt{6449}}{2*10}=\frac{-57+\sqrt{6449}}{20}
$